Then OP divides AB vertically (in g)

Angle OBP=90 degrees

Then AG=BG

In triangle OAG and triangle BOG

OG=OG angle OGA= angle OGB AG=BG

So the triangle OAG is equal to the triangle BOG.

So angel AOG= angel swamp

In triangle OAP and triangle BOP.

OA=OB angle OP=OP angle OP = OP

So the triangle OAP is equal to the triangle BOP.

So the angle OAP= the angle OBP=90 degrees.

So PE is the tangent of circle O.

(2) Are B and C bisectors of circle O, respectively? Right?