Then OP divides AB vertically (in g)
Angle OBP=90 degrees
Then AG=BG
In triangle OAG and triangle BOG
OG=OG angle OGA= angle OGB AG=BG
So the triangle OAG is equal to the triangle BOG.
So angel AOG= angel swamp
In triangle OAP and triangle BOP.
OA=OB angle OP=OP angle OP = OP
So the triangle OAP is equal to the triangle BOP.
So the angle OAP= the angle OBP=90 degrees.
So PE is the tangent of circle O.
(2) Are B and C bisectors of circle O, respectively? Right?