Formula: ∫ [0→π] xf (sinx) dx = (π/2) ∫ [0→π] f (sinx) dx.
Note: cos in the title? X can be seen as 1-sin? Therefore, x is a function of sinx.
This is the original example. See for yourself. If you need me to write the derivation process of the formula for you, ask again.
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