Two years ago, my father was 13 times as old as my son. Eight years later, the father is three times as old as his son. How old are my father and son now?

Answer and analysis: Two years ago, the father was older than his son (13- 1), and eight years later, the father was older than his son (3- 1). Because the age difference remains the same, 12 times two years ago and 2 times eight years later are equivalent to the same specific amount, but 18.

(1) Two years ago, the father was older than the son 13- 1= 12 (times).

(2) After 8 years, the father is 3- 1=2 (times) older than the son.

(3) Eight years later, it is twice that of my son two years ago: (8+2)x2=20 (years old),

(4)20 years old is several times my son's age this year: 12-2= 10 (times).

(5) How old was my son two years ago: 20÷ 10=2 (years old).

(6) How old was Dad two years ago? 13x2-26 (years old)

(7) Son's current age: 2+2=4 (years old)

My son and father are now 4 and 28 years old respectively.

Comprehensive formula:

My son's age now is (8+2) x2 ÷ [(13-1)-(3-1)]+2 = 4.

Dad's age now is 2x 13+2=28.