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Mathematics area problem of fifth grade in primary school.
From the meaning of the question: AB+AC=DE=8cm, so AC=4.5cm.

Given that CE= 13cm and the angle ACE is a right angle, the area of the triangle ACE is 4.5 *13/2 = 29.25cm..

The shaded area is the total area of the original paper minus the areas of the two triangular faces.

So the shadow area is13 * 8-4.5 *13/2 * 2 =13 * 8-29.25 * 2 = 45.5 square centimeters.