Suppose that the large rectangular area is S 1, the small rectangular area is S2, and the shaded area is S.

Then it is: S 1+S2-s= 156.

It is known that the overlapping area of two rectangles is equivalent to 1/8 of the large rectangular area and 1/6 of the small rectangular area.

There is s =1/8s1=1/6S2.

That is, S 1=8s and S2=6s.

The area ratio of (1) rectangle is =8s:6s=4:3.

(2)8s+6s-s= 156，s= 12

That is, the area of a large rectangle is 8* 12=96.

The area of the small rectangle is 6* 12=72.