Analysis: As shown in the figure, BC and CE can BE calculated by trigonometric function, BE can be calculated by trigonometric function, and EF can be calculated by the number of cars =(56-BE)÷EF+ 1.

Answer:

Solution: As shown in the figure, BC = 2.2× sin45 = 2.2× √ 2/2 ≈1.54m,

Ce = 5× sin45 = 5×√ 2/2 ≈ 3.5m，

BE=BC+CE≈5.04，

EF = 2.2÷sin 45 = 2.2÷2/2≈3. 14m，

[(56-5.04) ÷ 3. 14]+ 1 = [50.96 ÷ 3. 14]+ 1 ≈ 16+ 1 = 65438+

Therefore, this section can reserve at most 17 such parking spaces.

So the answer is: 17.