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2 yuan and 5 yuan split the money to do the math problem.
The first pile of money is at least: 5×2×2=20 (yuan)

Minimum value of the second pile of money: 5+2=7 (yuan)

The minimum value of two piles of money is: 20×7= 140 (yuan).

Two piles of money are at least: 140+ 140=280 (yuan).

Elegant bronze medalist Weng Jinwen answers your questions.

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