3x+y=2 1

X+y+z= 12(x is victory, y is flat and z is negative).

Then y= 12-x-z, substitute, 2x = 9+z.

Available, z= 1.x=5, y=6, meet the conditions.

Z=3.x=6, y=3, satisfying the conditions.

Z=5.x=7, y=0, which meets the conditions.