Solving college mathematics problems
There are 190 kinds of 2 products, 36 kinds 1 defective products, 1 2 defective products, so it is 37/ 1905 times, 10 kinds10 * (0.8) 2 * (. The ratio of 0.00 1=0.05 12 is 4: 3: 1, so there are eight first-class products: 4/8 =1/2e (x) = x1* p/kloc-0. 1)*P2 squared +( 1-0. 1)*P3 squared =0. 89p 1+P2+P3 = 1:p 1 = P2 = P3 =