So: ∠P'AB=∠PAC, AP'=AP=6, BP'=CP= 10.

So: ∠ p 'ap = ∠ p 'ab+∠ PAB = ∠ PAC+∠ PAB = ∠ CAB = 60.

So: △P'AP is an equilateral triangle.

So: P'P=PA=6.

Also: △P'AP is an equilateral triangle.

So: ∠ p 'pa = 60.

Also: PP'=6, BP'= 10, BP=8.

So: △P'BP is RT△

So: ∠ p 'pb = 90.

So: ∠ APB = ∠ p 'pb+∠ p 'pa = 90+60 =150.