Dear math lover: Your luck has come. Listen to the question: the cube of A minus the square of 6a plus 1 1a minus 6. (This problem is factorization. )
a^3-6a^2+ 1 1a-6=a(a^2-6a+9)+2(a-3)
=a(a-3)^2+2(a-3)
=(a-3)(a^2-3a+2)
=(a-3)(a- 1)(a-2)
That's it. If you think you can, give me the best answer.