Solution: 2 hours and 30 minutes = 150 minutes.
If Party A and Party B leave at the same time, Party B will arrive at B earlier than Party A150+10 =160.
So at the same distance, the time ratio of Party A and Party B = the inverse ratio of speed = 5: 1.
Then the time taken for the whole journey of line B is 0/5 of that of line A+65438.
Therefore, the whole journey time of Line A =160/(1-1/5) = 200 minutes.
Time taken for the whole journey of the second line =200- 160=40 minutes =2/3 hours.
Speed b = 60/(2/3) = 90km/h.
98. The distance between Party A and Party B is 960 kilometers. The express train leaves Station A for bilibili at 5 a.m., and the local train leaves bilibili for Station A at the same time. The two trains meet at 1 1 in the morning. When will the express train arrive at bilibili at 3 pm and the local train arrive at Station A?
Solution: 165438+ 0 am to 3 pm * * * is 4 hours.
Meeting time = 1 1-5=6 hours.
Time for the express train to complete the journey =6+4= 10 hour.
Express speed = 960/10 = 96 km/h.
The sum of the speeds of two vehicles = 960/6 =160 km/h.
The speed of the local train =160-96 = 64 km/h.
It takes 960/64= 15 hours for the local train to complete the journey.
So the time for the local train to arrive at Station A is 5+ 15=20 in the afternoon.