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The seventh grade mathematics problem book 2
Solution: AB = BC AD is the midline on the BC side of △ABC.

∴DB=DC= 1/2AB

Ad divides the circumference of triangle ABC into 3 and 4 parts.

∴(ab+ 1/2ab):( AC+ 1/2ab)= 3:4

∴4(ab+ 1/2ab)=3( AC+ 1/2ab)

AB=2/3AC

Or ∴ (ab+1/2ab): (AC+1/2ab) = 4: 3.

∴3(ab+ 1/2ab)=4( AC+ 1/2ab)

AB=8/5AC