Process: Let the shortest side be X, and the other two sides be x+ 1 and x+2.

Then x 2+(x+ 1) 2 = (x+2) 2.

Solving x is 3.

The other two parties will know.

2. 1 solution: let the variable length of this square be a.

Then (a+2)(a+5)=54.

The solution is a=4.

2 solution: let the smallest integer be x, then the other two integers are x+ 1 and x+2.

x(x+ 1)+x(x+2)+(x+ 1)(x+2)= 242

Sorry, I don't have any draft paper. You can solve it yourself.

3. solution: let the length of bamboo pole be x.

Then (x-4) 2+(x-2) 2 = x 2.

4. let one number be x and the other number be 6-X.

Then x(6-x)=7.

Solution x= Please do the math yourself.

5. Simplify and get MX 2-3mx+X-3 = m-2.

mx^2+(-3m+ 1)x+(-3-m+2)=0

If the sum of the coefficients is 3, then m+(-3m+ 1)=3.

Only need to solve m.