1) Let one side parallel to the wall be xm and the other side be (20-x)/2m.

According to the meaning of the question,

x(20-x)/2=48，

Finishing: x 2-20x+96 = 0,

(x-8)(x- 12)=0，

x 1=8，x= 12

So there are two cases, that is, the length and width are 8,6, or12,4.

2) Because the wall length is 10m, and12 >; 10

So there is only one case, the length and width are 8, 6.