Ninth grade math-central angle and peripheral angle. - Training Enrollment Network

Ninth grade math-central angle and peripheral angle.

1)∠CPD=∠COB, ∫ ABCD ∴ AB bisecting arc CD∴∠CPD= semi-arc CD=∠COB.

2) connect point P 1 with point c and point P 1 with point d to obtain a quadrilateral CPDP 1 inscribed in a circle.

∠ cp 1dd+∠ CPD = 180 (diagonal complementation of quadrangles inscribed in a circle)

∫∠COB =∠CPD

∴∠CP 1D+∠COB= 180

That is, ∠CP 1D and ∠COB are complementary.

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