Because there are few combinations, the exhaustive method can be used. If there are many times, the permutation and combination method is recommended. Then calculate according to the classical probability (equal probability event).

The following is the understanding that 1, 5,6 can only be selected once (meaning that there is no such thing as 1 1, 55,66).

First of all, there are only six cases: 15,16,5156,6165, and the probability of each case is the same (that is, one sixth).

Empty one: Since it is singular, the last digit can never be 6, 15, 5 1, 6 1, 65, so the possibility is 4/6=2/3.

Empty two: even number is opposite to odd number, so it is 1/3.

Empty three: The number divisible by 2 is even, so it is 1/3.

Empty four: The characteristic of a number divisible by 5 is that the last digit is 5 or 0, so only 15 and 65 meet the conditions, and the possibility is 1/3.

Empty five: The number divisible by 2 and 3 at the same time must be even, so the last digit must be 6, and the sum of the two numbers can be divisible by 3. None of the above six figures is satisfactory, so fill in 0.