Math test paper grading reference
First, multiple-choice questions (***8 small questions, 4 points for each small question, ***32 points)
Title 1 2 3 4 5 6 7 8
Answer a d b c b c d
Fill in the blanks (***4 small questions, 4 points for each small question, *** 16 points)
Title 910112
answer
- 15 8
III. Answer questions (***5 small questions, ***25 points)
13. (Full score for this small question)
Calculation:
Solution:
= ... 4 points.
= ......................................................... 5 points.
14. (Full score for this small question)
Solving inequality system
Solution: If inequality ① is solved, x < 2. ................................................................................................................................................................
If inequality ② is solved, x >- 1 ..........................................................................................................................................................
The solution set of the original inequality group is-1 < x < 2. .............................................................................................................................................
15. (Full score for this small question)
Prove,
∴, .............................. 2 points.
Say it again,
∴ ............................................ 3 points.
At △ABC and △CDE,
.................................................., 4 points.
∴ BC = 5 points in ...........................................................
16. (Full score for this small question)
Solution:
.........................................., two points.
Three points
..........................................................., 4 points.
When, the original type of ............................................................ 5 points.
17. (Full score for this small question)
Solution: (1)∵ Image passing point of inverse proportional function,
∴ .
∴ The analytical formula of inverse proportional function is .................................................................................................................................................................
This point is on the image of the inverse proportional function,
∴ .
∴ ............................................. 2 points.
(2) When or, the value of the linear function is greater than the value of the inverse proportional function ...................... by 4 points.
(3) The analytical formula of the function image obtained by moving the linear function image to the right by 1 unit length is y =-x ... five minutes.
Iv. Answer questions (***2 small questions, * * 10)
18. (Full score for this small question)
Solution: As shown in the figure, point A is AF⊥BC, and point F is ............................................ 1 min.
∠D=90，
∴ .
Say it again,
The quadrilateral AFCD is a rectangle.
∴ FA = CD = ........................................... 2 points.
In Rt△AFB, ∠ b = 60,
∴BF = af÷tan 60 = 4 ...............................................................................................................................................
∴ AD = FC = BC-BF = 9-4 = 5 ..................................................... 4 points.
In Rt△ADE, ∠ d = 90,
,
∴ .
∴ ...........................................................................................................................................................................
19. (Full score for this small question)
Solution: (1) The straight line CE is tangent to ⊙ o. 。
Proof: As shown in the figure, link OD.
Advertising sharing ∠FAE,
∴∠CAD=∠DAE.
OA = OD，
∴∠ODA=∠DAE.
∴∠CAD=∠ODA.
∴OD‖AC.
∵EC⊥AC，
∴OD⊥EC.
∴CE is the tangent of⊙ O, and ....................................................................................... is 2 points.
(2) As shown in the figure, connect BF.
∵ AB is the diameter⊙ O,
∴∠ Air base =90 degrees.
∫∠C = 90，
∴∠AFB=∠C.
∴BF‖EC.
∴ af: AC = company.
∫AF∶FC = 5∶3，AE= 16，
∴5∶8=AB∶ 16.
∴ AB =10 ........................................................... 5 points.
V. Answer the question (the full mark of this question is 5 points)
20. (The full score for this short question is 5)
Solution: (1) Complete figure 1 and figure 2 ... 2 points.
(Ben)
These 65,438+000 students read three extra-curricular books in one semester on average, and ....................................................................................................... scored 3 points.
3000×3=9 000 .
It is estimated that students in this school read 9000 extracurricular books in one semester. ..............................................................................................................................................................
(3) If you can put forward a positive view according to the chart, score 5 points.
Six, answer (***2 small questions, * * 10)
2 1. (Full score for this small question)
Solution: Class A donated X pieces of stationery and Class B donated Y pieces of stationery. .........................................................................................................................................................
According to the meaning of the question, get 3 points.
Solution ... 4 o'clock.
Answer: Class A donation 120 pieces of stationery, and Class B donation 140 pieces of stationery ........................................................ scored 5 points.
22. (The full score for this short question is 5)
Solution: (1) The three spellings are1... 3 points each.
(2) The area of the parallelogram spelled by the three methods is a fixed value, which is12 .......................................... 4 points.
(3) The perimeters of parallelograms spelled by the three methods are not fixed values, but their perimeters are,
Five points.
Seven, answer the question (this question out of 7 points)
23.( 1) proof: order.
Get delta = =。
No matter m is any real number, it has > 0, that is, △ > 0.
This equation has two unequal real roots.
∴ Whether m is any real number or not, the image of quadratic function has two intersections with the X axis, and .................................................................... scores 2 points.
(2) Solution: The opening of the quadratic function image is upward, and the two intersections with the X axis are on both sides of the point (1, 0).
When x= 1, y = 12+2m+m-7 < 0.
M < 2。 ①3 points.
The univariate quadratic equation about x has two real roots,
∴△= ≥0，m2 ≠ 0。
The solution is m ≥, m≠0. 24 points.
M is an integer,
According to ① and ②, the value of m is 1 ............................................................................................................................................................
(3) Solution: When m= 1, the equation is.
By finding the root formula, we get.
∴ x =-2a- 1 or x =-1................................................................. 6 points.
The equation has a real root greater than 0 and less than 5,
∴0