A math review problem in senior three.

Let AD be perpendicular to BC in D, so AD is perpendicular to plane BB' c' c and connected to DC', so ∠ AC' d is the angle formed by AC' and plane BB' c' c; Let the side length be a, AD⊥DC', AC'=√2a, and C'd = ∠ 5a/2, so cos ∠ AC'd = c'd/AC' = √ 5a/2/√ 2a = √14.

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