Then, among the 100 people, at least (
) people have passed.
The solution first solves the original problem. The number of wrong answers to each question is (the order is not important): 26,265,438+0,654,38+09,654,38+05,9.
Distribution level 3: The maximum number of people who answered three questions incorrectly is (26+21+19+15+9)/3 = 30.
Distribution level 2: The maximum number of people who answered two questions incorrectly is (21+19+15+9)/2 = 32.
Distribution layer 1: The number of people who answered the question incorrectly 1 is: (19+15+9)/1= 43.
Max_3=Min(30，
32,
43)=30。 So the answer is: 100-30=70.
In fact, because 26 is less than 30, it can be judged that the answer is 70 after finding the first distribution layer.
In order to minimize the number of people who pass, we must do two things:
1.
Those who fail answer as many questions as possible, which reduces the number of questions that those who pass need to answer correctly, and only fewer people pass.
2.
Everyone who passes the exam answers as many questions as possible, which can also reduce the number of people who pass the exam.
Everyone at 1 answered at least two questions correctly.
Starting from 2, we must assign the remaining 2 10 questions to 70 of them:
2 10/3
=
70, let these 70 people all answer correctly, while the other 30 people only answered two questions correctly.
It is also easy to give specific embodiments:
Let 70 people answer all five questions correctly, 1 1 Only the first and second questions were answered correctly, 10 only the second and third questions were answered correctly, five people answered the third and fourth questions correctly, and four people answered the fourth and fifth questions correctly.
Obviously, a slight change will increase the number of people who pass the exam. So the minimum number of people passing is 70.