Bus speed 20÷5= 4 times that of walking.

It takes 1/4 to walk the same distance.

Therefore, the whole walking of 1- 1/3=2/3 requires:

15 ÷ (1-1/4) = 20 minutes

To complete the course, you need:

20÷2/3=30 minutes =0.5 hours

The distance from home to school is: 0.5× 5 = 2.5km.

2.

When Party A and Party B meet, the journey is 5 1×2= 102 km.

A walked for 6- 1.5=4.5 hours.

B walked for six hours.

A's 4.5-hour journey is more than B's 3×4.5= 13.5-hour journey 1×4.5=4.5 kilometers.

The speed of B is (102-4.5) ÷ (6+13.5) = 5 kilometers per hour.

A the speed is 5×3+ 1= 16 kilometers per hour.

3.

(700-480)÷(90+ 1 10)

=220÷200

= 1. 1 hour

A: After 1. 1 hour, the distance between the two cars is 700 kilometers.

4.

5 hours and 30 minutes = 1 1/2 hours

1 Based on the distance between Party A and Party B..

Bon voyage every hour1÷11/2 = 2/11.

The headwind is 65438 per hour+0/6 of the whole journey.

The hourly wind speed is (2/1-1/6) ÷ 2 =1132.

The distance between the two cities is: 24 ÷1132 = 3168km.

5.

1)

(162-60× 0.5) ÷ (48+60)+0.5 = 3118 hours.

A: The two cars met in 3118 hours.

2)

There are two situations.

The two cars haven't met yet.

Need (162-54) ÷ (48+60) =1hour.

② After the two cars meet, they are 54 kilometers apart.

It takes (160+54) ÷ (48+60) =1.5 hours.

1.

Solution: it's x kilometers from home to school.

( 1- 1/3)x/5-( 1- 1/3)x/20 = 15/60

2x/ 15-x/30= 1/4

x/ 10= 1/4

x= 10/4

x=2.5

It's 2.5 kilometers from home to school.

2.

Solution: Let the speed of B be x kilometers per hour, then the speed of A is 3x+ 1 kilometer per hour.

(6- 1.5)(3x+ 1)+6x = 5 1 * 2

4.5(3x+ 1)+6x= 102

13.5x+4.5+6X= 102

19.5x=97.5

x=5

3x+ 1= 16

A: A speed 16 km/h and B speed 5 km/h..

3.

Is this a question of time?

Solution: Suppose the distance between two cars is 700 kilometers after X hours.

(90+ 1 10)x+480=700

200x=220

x= 1. 1

A: After 1. 1 hour, the distance between the two cars is 700 kilometers.

4.

5 hours and 30 minutes =5.5 hours

Solution: Let the distance between two cities be X kilometers.

x/5.5-24=x/6+24

x( 1/5.5- 1/6)=48

x/66=48

x=66*48

x=3 168

A: The distance between the two cities is 3 168 km.

5.

1)

Solution: Suppose two cars meet in X hours.

48(x-0.5)+60x= 162

48x-24+60x= 162

108x= 186

x=3 1/ 18

A: The two cars met in 3118 hours.

2)

The two cars haven't met yet.

Solution: Suppose the distance between two cars is 54 kilometers after X hours.

(48+60)x+54= 162

108x= 108

x= 1

A: After 1 hour, the distance between the two cars is 54 kilometers.

② After the two cars meet, they are 54 kilometers apart.

Solution: Suppose the distance between two cars is 54 kilometers after X hours.

(48+60)x= 162+54

108x=2 16

x= 1.5

Answer: 1.5 hours later, the distance between the two cars is 54 kilometers.