Y = y = symmetry center of cosx: (kπ+π/2,0) (k ∈ z)

According to the image of sine (cosine) function, it can be seen that 9, y=cosx is an even function, and only the symmetry center of x=k*pi, 2, y=sinx is (kπ, 0)(k∈Z).

The symmetry center of y=cosx is (π/2+kπ, 0)(k∈Z), 1, which is the symmetry center of images and properties of trigonometric functions in high school.

The symmetry center of y=sinx is x=kπ, and y=0.

What about the symmetry center of y=cosx?