A(a, -2) and point B (3, b) are symmetrical about X, that is, the abscissa of A and B are equal and the ordinate is opposite, so that a=3 and b=2 can be obtained.

Point C(a, b) and point D(x, y) are symmetrical about the origin, that is, the abscissa and ordinate of C and D are opposite, and X =-A =-3 and Y =-B =-2 can be obtained.

The second question:

Simultaneous y=-3/x and y=-x+2, we can get x 2-2x-3 = 0, we can get x 1=- 1, x2=3, so we can get y 1=3, y2 =-/kloc-0.

So the coordinates of A and B are (-1, 3) and (3, 1).

Since the distances between point A and point B are equal to the origin O, the area of triangle AOB can be obtained with the length of AB as the base and the distance between point A and point O in AB as the height.

The midpoint of AB is (1, 1), the distance to the origin is √2, and the length of AB is 4√2.

So the area S=4√2*√2/2=4.