Analyze known conditions:
1. The ages of the five children should be different (it is meaningless for the questioner to set the children's ages the same)
Two, nine and 13 cannot be divisible by 18480, so there are no these two numbers.
Thirdly, there is no such number as 1, because the product of the four largest numbers except 9 and 13 (12, 1 1 and 8) is less than 18480. In other words: if 1 exists, the other four children will be older than 13.
Fourth, it is divided into three parts. (This part mainly analyzes 12, 1 1 and 10. )
1, assuming that the largest two digits 12, 1 1 and 10 all exist, then the number is 14 after dividing by 18480. Only 2*7 matches. However, the combination of 12, 1 1,/kloc-0, 7,2 does not meet 37, so 12, 1 1.
2. Since the numbers 12,1and 10 cannot exist at the same time, it is assumed that the smallest number in the largest two digits 10 does not exist, that is, the ages of two children are 12 and10 respectively. And 5*5*5 is less than 140, so there is no number below 5 (the logic of this passage is: if two digits are not the largest, that is, 1 1 and 12 exist, then the product of the other three numbers will be greater than 140, so there is 5.
As the number below 5 does not exist, the remaining three children can only be 6, 7 and 8. And 12, 1 1, 8, 7, 6 and 12, 10, 8, 7, 6 and1/kloc-0. Therefore, the possibility of the existence of two digits is ruled out, so there can only be one digit, that is, one of 12, 1 1 0. If there is only one number in 12, 1 1 0, then there is no number below 5 (if 12 and 1 1 both exist, there can be no number below 5). After we determined the four numbers of 8, 7, 6 and 5, we soon knew that the remaining two numbers only matched 1 1.
4. So the answer is: 1 1, 8, 7, 6, 5.