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A math problem
Ten dollars can buy five bottles of wine;

Drink for the first time:

There are 5 bottle caps, and you can change 1 bottle of wine, and then there are 1 bottle caps left;

There are 5 empty bottles, you can change 2 bottles of wine, leaving 1 empty bottle;

Then a * * * gets three bottles of wine,

Drink it for the second time,

Three caps, three empty bottles, drink the rest for the first time.

A * * * has four bottle caps and four empty bottles.

Four bottle caps can be exchanged for 1 bottle of wine,

Four empty bottles can be exchanged for two bottles of wine and one * * * can be exchanged for three bottles of wine;

Drink for the third time:

There are three bottles of wine with three caps,

Three empty bottles can be exchanged for 1 bottle of wine, leaving 1 empty bottle;

Drink for the fourth time;

And 1 empty bottle 1 bottle cap, plus the bottle cap and empty bottle left over from the third time.

A * * * has four bottle caps and two empty bottles.

You can get 2 bottles of wine;

Drink for the fifth time:

There are two empty bottles and two caps.

You can take a bottle of wine and there are two bottle caps left;

After drinking for the sixth time,

Finally, * * * left an empty bottle and three caps.

To sum up: a * * can drink 5+3+3+1+2+1=15 (bottle).