Current location - Training Enrollment Network - Mathematics courses - Math problem in the second day of junior high school! ! Seek expert answers. 2√3X=√2(X? +1) You will get extra points if you do it well.
Math problem in the second day of junior high school! ! Seek expert answers. 2√3X=√2(X? +1) You will get extra points if you do it well.
2√3X=√2(X? +1) The square on both sides is 12X? =2(X? + 1)?

Simplify (x? -2)? =3 solution x? =2-√3 or 2+√3

x? =2-√3 2X when both sides are multiplied by 2? =4-2√3=3-2√3+ 1=(√3- 1)? Solve X= addition and subtraction (√3- 1)/√2.

Can you still find X? The solution of =2+√3 is X= plus or minus (√3+ 1)/√2.

Because the left side of the original formula is 2√3X, and the right side must be a positive number, so we should abandon the negative solution.

So the answers are (√3- 1)/√2 and (√3+ 1)/√2.

Thanks for your hard work. I hope to adopt O (∩ _ ∩) O. Thank you.