The first volume of the second day of junior high school mathematics chapter 1 1 examination paper (with answers).

Equal triangle exercise (2)

First, fill in the blanks:

1. In △ABC, if AC > BC > AB, and △DEF △ ABC, then the triangular relationship of △ def is _ _ < _ _ _ _ _.

2. As shown in figure 1, where AD⊥BC and D are the midpoint of BC, then △ Abd _ _, △ABC are _ _ triangles.

3. As shown in Figure 2, if AB = DE and BE = CF, to prove △ ABF △ DEC, you need to supplement the condition _ _, or _ _.

4. As shown in Figure 3, it is known that AB‖CD, AD‖BC, E and F are two points on BD, and BF = de, then there are _ _ _ pairs of congruent triangles in * * * in the figure, which are _ _ _ _ respectively.

5. As shown in Figure 4, the diagonal of the quadrilateral ABCD intersects at point O, and there are AB‖DC and AD‖BC, then there are _ _ pairs of congruent triangles in the figure.

6. As shown in Figure 5, it is known that AB = DC, AD = BC, E and F are two points on DB, BF = DE. If ∠ AEB = 120, ∠ AD=BC = 30, ∠ BCF = _ _ _ _

7. As shown in Figure 6, AE = AF, AB = AC, ∠ A = 60, ∠ B = 24, then ∠ BOC = _ _ _ _.

8. In isosceles △ABC, AB = AC = 14cm, E is the midpoint of AB, DE⊥AB is in E, and AC is in D. If the circumference of △BDC is 24cm, the bottom BC = _ _ _ _.

9. If △ AB' c' △ A 'b 'c' and AD=A'D' A' d' are the heights of the corresponding sides BC and B 'c' respectively, then △ Abd △ A 'b'd' is based on _ _ _ _ _ _, so AD = A' d', which is.

10.Rt△ABC ∠ c = 90, and the bisector of ∠A and ∠B intersects o, then ∠ AOB = _ _ _ _.

Second, multiple-choice questions:

1 1, as shown in Figure 7, △ ABC △ bad, A and B, C and D are the corresponding vertices respectively. If AB = 6 cm, AC = 4 cm and BC = 5 cm, then the length of AD is ().

A, 4cm B, 5cm C, 6cm D, all of the above are wrong.

12, the following statement is true ()

Two triangles with equal perimeters are congruent.

Two triangles have two opposite angles, one of which is congruent.

C, congruence of two triangles with equal areas

D, two triangles with two angles and opposite sides of one angle are congruent.

13. In △ABC, ∠ b = ∠ c, and one angle of the triangle congruent with △ABC is 100, then the angle corresponding to this angle 100 in △ABC is ().

A, ∠A B, ∠B C, ∠C D, ∠B or ∠C.

14, the following conditions, can determine the △ ABC △ def is ().

A、AB=DE，BC=ED，∠A=∠D

b、∠A=∠D，∠C=∠F，AC=EF

c、∠B=∠E，∠A=∠D，AC=EF