Math prawns, come in! Please look at the personal original plane geometry problem (grade six): find the area of 1 circle (for example)

According to the given conditions, the most triangles are isosceles right-angled triangles, and both given right-angled sides are root 8.

pythagorean theorem

Square of hypotenuse = square root of 8+square root of 8.

Square of hypotenuse =8+8

Square of hypotenuse = 16

Hypotenuse =4

According to Pythagorean theorem, the hypotenuse of another right triangle is calculated.

Square of hypotenuse = square of 3+square of 4.

Square of hypotenuse =9+ 16

Square of hypotenuse =25

Hypotenuse = 5

Here the hypotenuse is the radius of the circle.

According to the area formula of a circle = π× the square of radius

This is a quarter circle.

It is the square of a quarter × π× radius.

= 1/4× 5 squared

= a quarter ×25π

=6.25π