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Who will wait online for the third grade mathematical formula method?
Assumed width xdm

The length is x+5 dm.

The volume is length * width * height =(x+5)*x*8=528.

= = & gt8x^2+40x-528=0

= = & gtx^2+5x-66=0

= = & gt(x+ 1 1)(x-6)=0

= = & gtX=- 1 1 (irrelevant, omitted)

x=6

So the width is 6 dm.

The length is 1 1 dm.