Is there a problem with the first one ... O(∩_∩)O Haha ~ Is the second one A? The function f(x)=tan(ωx+ψ), (ω > 0), and the condition p: "f (0) = 0"; So ψ=0+kπ, and tan(0+kπ) are all 0. Expand tan(ωx+ψ), tanωx=-tanωx, so it is odd function. Because it is odd function, f(0)=0, so the answer is A. It may be wrong ... I haven't touched it for a long time. ...