Question 1: 2/7

Question 2:112

We correctly understand the meaning of the second question, obviously asking you what happens when the mouse comes out of the inner door. Be careful not to ask you that the mouse came out from the inner door.

After the mouse comes out from the inner layer, you can select 12 doors, that is, 2 doors can re-enter the inner layer, 5 doors cannot be opened from the inner layer, and 1 doors cannot be opened from the outer layer. The title requires "you can find the exit of the outer maze once", which means that as long as you can't open the door in front of a certain door, or as long as you go back to the inner layer, you won't succeed, so the correct one should be1(2+5+1+4) =112.

Having said that, I will extend the topic (belonging to the high school level): If the mouse starts from the inner black spot, what is the probability that it can find the exit of the outer maze at one time? Then the answer is: (2/7) × (112) =1/42. Simply put, it is an event to walk out of the inner layer from the black spot, and another event to walk out of the outer door from between the inner and outer layers. When these two events are considered together, multiplication is used.