As shown in the figure, the geometry formed by the rotation of △ABC around the straight line BC is a cone CAD minus a small cone BDA, and the bottoms of the two cones are the same, AD⊥CD, ∫in△Abd, ∠ Abd = 60? ,AB=2,∴AD=√3,BD= 1,CD=2.5
V-cone = 1/3 * π * ad? *CD=2.5π
V-cone = 1/3 * π * ad? *BD=π
V geometry = v big cone -V small cone = 2.5 π-π = 1.5 π.