Five digits × 4 = five digits, so A can only be 1 or 2, and E can only be 8 or 9. Because the multiplier is 4, a=2.

If several numbers are A, that is, 2, then E can only be 8, and e=8.

Then push b, 2xxxxx× 4 = 8xxxx, then b can only be 0, 1, 2.

The unit 8× 4 = 32,3 is decimal, so the product remainder of 4×d can only be 0+ 10-3=7 or 1+ 10-3=8 or 2+10-3 = 9,7,8.

When d=2, the decimal number of molecule b is 1, when d=7, b is also 1, and when b= 1, d≥4, so d can only be equal to 7.

The formula becomes 2 1c78×4=87c 12.

78×4 decimal number 3, c×4 decimal number followed by decimal number +3 equals C, and there is only one such number, that is, 9.

So c=9

The original number is 2 1978.