This doesn't hold, so a≠0.

When a>0, let the function f(x)=ax? -ax+ 1

Then the function image is a parabola and the opening is upward,

So when △=a? When -4a < 0, that is, 0 < a < 4, the parabola has no intersection with the X axis, so the original inequality has no solution.

When a=4 and △=0, there is only one intersection point between parabola and X axis, so the original inequality still has no solution.

When a>4 o'clock, △ > 0, parabola and X axis have two intersections, so the solution set of inequality is:

【a-√(a？ -4a)]/2a