Compulsory Math 2: Find the equation of circle passing through three points O (0 0,0), M 1 (1, 1), M2 (4 4,2). . After f, it is +2, +20. How did it come about?
X 2+Y 2+DX+EX+F = 0 is a general equation of a circle.
F=0 is the result of introducing O (0,0).
M 1( 1, 1) is brought into 1+ 1+D+E+F=0, that is, D+E+F+2=0.
M2 (4,2) brings 16+4+4D+2E+F=0, which means 4D+2E+F+20=0.
I hope it helps you! ↖(^ω^)↗