When t= 1, x= 1, y=2, Z = 1. X' = 1, Y' =- 1, Z' = 2, then the tangent equation of the curve is X- 1 =.

At this time, the tangent is the normal of the normal plane, so we can know that the equation of the normal plane is (x-1)-(y-2)+2 (z-1) = 0.

Hope to adopt.