5. the zero point is the intersection with the x axis.

Therefore, the method of selecting the interval is to multiply the number obtained by the coordinate substitution formula by less than zero.

∫log(2)2+2-4 =- 1，log(2)3+3-4≈ 1。

∴ Multiplication is less than zero, so choose C.

7. After translation, 2sin(X-π/6) ∵ symmetry axis x=π/2+kπ is obtained.

K is an integer.

∴ X-π/6=π/2+kπ

When K=- 1, X=-π/3.

Choose C.

8. The equation of a circle is (x-3) 2+y 2 = 4.

∴ center c (3,0) r = 2

And asymptote equation is y= (plus or minus b/a) x.

It can be changed to: bx/a-y=0, and the other one is omitted.

According to the tangency, the distance from the center of the circle to the straight line is the radius, ∴I3b/aI/ (b/a) 2+ 1 = 2.

Center c is the correct focus.

∴c=3,∴b^2=9-a^2

Substituting the above formula, we get 9a 2-45 = 0 ∴ A = root number 5.

∴a^2=5,b^2=c^2-a^2=9-5=4

The equation is x 2/5-y 2/4 =1.

choose one

10. Parallel, so the coordinates cross and multiply equally, 2X2=X- 1.

∴X=5

1 1∶y = bx/a

Let b = 4m, a = 3m and c = 5m.

Eccentricity e=c/a=5m/3m=5/3.