(2)A(-2 radical 3,0), B(2 radical 3,0),
Let b and d be AC vertical lines respectively. Let the intersection of AC and BD be e.
Triangle ACD= triangle ACB area = 1/2*AC* height.
So the height is equal. The certificate is congruent. Get BE=DE.
So AC divides BD equally.
Just asking. ...
(3) existence. AB=4 times the root number 3,
The distance from the highest point of parabola to A =4 times the root number 3, p (0,6),
You continue to testify ~