Learn a, calculate b, learn c and love d, that is, e,

Then it is:

abc+dbc+edbc= 1922，

The last digit is 2, that is, the last digit of the sum of three C's is 2, so C = 4；;

Then the penultimate digit is equivalent to the sum of three B's, and the last digit is 1 (because three C's are 12, carry 1), so B = 7；;

There are thousands of digits. E cannot be 0, so E can only be 1, that is, E =1;

Now there are only a few hundred digits left, that is, a+2d=9-2=7.

If d= 1, then a = 5；; D=2, then a = 3；; D=3, then a= 1.

So I love math, that is, e+d+b+c= 13 or 14 or 15.

Ok, if you have any questions, please ask me.

Ps, I don't like math. I don't like math. I don't like math.