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Mathematics and geometry problems in the second day of junior high school
Solution: AB=AE=AF=AD

∠B=∠D

So triangle ABE is congruent with triangle AFD.

BE=DF

Then CE=CF

CEF= Treaty on Conventional Armed Forces in Europe

∠CEF+∠CFE+∠C= 180

∠B+∠C= 180

So ∠B=∠CEF+∠CFE=2∠CEF.

∠B=∠AEB

∠AEB=2∠CEF

∠AEB+∠AEF+∠CEF= 180

2∠CEF+60 +∠CEF= 180

∠CEF=40

∠B=80