Germany divides ∠ ADC and EC ⊥ DC into two parts.

∴EC=EF

EC = EB

∴EF=EB

∵EB⊥AB

Ae segmentation ∠DAB

∠∠C =∠B = 90

∴AB‖DC

∴∠CDA+∠DAB= 180

∫∠CED = 35

∴∠CDE=90 -35=55

∴∠CDA= 1 10

∴∠DAB=70，∠EAB=35