If E is a parallel line L between AB and CD, then L divides the two parts of the angle E into inner angles on the same side with angles ABE and CDE, respectively.

So angle E+ angle ABE+ angle ADE = 180+ 180 = 360 degrees.

Because the angle E = 1 10 degrees, the angle ABE+ the angle ade = 360-1/kloc-0 = 250 degrees.

So FBE angle +FDE angle = 1/2 * 250 = 125 degrees.

Because the sum of the internal angles of the quadrilateral is 360 degrees,

Therefore, the angle f = 360-125-10 =125 degrees.