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Late mathematical problems
One student wants to go from home to school. At first, he walked at a speed of 50 meters per minute. After walking for 2 minutes, he calculated that if he walked like this, he would be 8 minutes late. If there is 10 meter per minute, he will arrive at school five minutes early. Can you tell me the distance from home to school?

Elementary school problems are solved by arithmetic first;

If the speed is 50 meters per minute, he will be 8 minutes late, that is, by the time of class, he will be 50*8=400 meters away from school.

Go ahead 2*50= 100 meters. If you change the speed to 50+10 = 60m/min, you will arrive five minutes earlier. So if he had walked at a speed of 60m/min from the beginning, he would have arrived early: 5+(2- 100/60)=5 and 1/3.

If he keeps walking after school, he will walk more by class time: 60* 16/3=320 meters.

Then the time from home to school is: (400+320)/(60-50)=72 minutes.

The distance from home to school is: 50 * (72+8) = 4000m.

Solve by equation:

Suppose the class time from home to school is X.

50*(X+8)=50*2+(X-2-5)*60

X=72

Then the distance is: 50 * (72+8) = 4000m.