This is a problem of finding the minimum surface area. That is, you have to find a way to minimize the surface area of this cuboid. You will find that the closer you are to the cube, the smaller its surface area. According to this rule, we divide the box of 10 into two piles, one pile of five, and the two piles are parallel. This cuboid is; The length is 10, the width is 12 and the height is 10. The surface area of this cuboid is the smallest area of cardboard: (10+12) x2x15438+00x12x2 = 680.