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How to do the question 12 of "the concept and expression of function" in the second stage of compulsory mathematics for contemporary middle school students?
1, because when 0≤g(x)≤ 1, for y=f[g(x)], when x is greater than or equal to 0, it is equal to 1, so y= 1, similarly-1≤ g.
For y=f[g(x)], when x = 0, it is equal to 0, so y=0.
2. In fact, you can draw the graphs of these two functions from the above, draw the graphs of -f(-x), and find the analytic expression of f(x)-f(-x), which is g(x). So f(x)-f(-x)=g(x)