2. Investigate the topic, which says that at least one person has been admitted to the university.

Including: A was admitted to B but not admitted, A was not admitted to B, and both A and B were admitted.

So, method one:

The three situations add up.

0.6*( 1-0.7)+( 1-0.6)*0.7+0.6*0.7=0. 18+0.28+0.42=0.88

Method 2:

Excluding the probability that neither of them was admitted is the probability that at least one person was admitted.

1-( 1-0.6)*( 1-0.7)= 1-0. 12=0.88