Analysis: Because quadrilateral ABCD and quadrilateral EFGH are two identical right-angled trapezoids, the areas ① and ③ are equal. If BC and HG intersect at point M, the area of area ③ is equal to the area of trapezoid FGMB minus the area of triangle GMC. Find the area of ③ and get the area of ①.

Solution: According to the meaning of the question, it is concluded that the area of area 1 is equal to the area of area 3. Extend BC and HG at point m.

Then the area of area ③ = 1/2 (200+200-4) × 2 = 396m2.

∴ ① The area is 396 square meters.

This problem should be able to convert the required area into a figure with known numbers and solve it.

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