a-b+c= 10

4a+2b+c= 1

9a+3b+c= 1

The solutions are a= 1, b=-4 and c=5.

So y=a? -4x+5，

y=(a-2)？ + 1

The vertex coordinate is (2, 1), that is, point B is the vertex.

The coordinate of the intersection of E and X axis after rotation is E (1, 0).

If the intersection b is perpendicular to the X axis and the vertical foot is m, then m (2 2,0).

S δ BDE = S quadrilateral BMOD-S δ BME-S δ EOD

=(5+ 1) 2÷2- 1 1÷2-5 1÷2

=6- 1/2-5/2=3

In addition, the analytical formula of the rotated image is no longer called "function", but it can still be expressed by analytical formula, but this is not the knowledge of junior high school. The original intention of this problem does not need to rotate the analytical expression of the image.