However, in the triangle, these two propositions are true, (I guess you must be confused here, too)
Because in a triangle, the big side faces the big corner, and the big corner faces the big side;
So:
① Sina & gtSinB, according to sine theorem, a/sinA=b/sinB=2R.
So a = 2RSina >; 2RsinB=b
Then, from "big side to big angle", we get: a >;; B
(2) It can be inferred from (1) in turn.
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