That is, (m 2+m-2) m-(m 2+m-2)+8 = 0.

So 2am-2a+8=0, that is, am-a+4=0, so m= 1-4/a*

Let h (x) = ax 2+bx+c.

Bring * into f (x) and h (x), and you get:

a^3+6a-8=0**

Aa^3+Ba^2+(c- 1)a+4=0***

Multiply * * * by -2 to get:-2aa3-2ba2-2 (c-1) A-8 = 0 * * * *, and compare with * * to get: C=-2,

That is, h (0) =-2

So choose one

This set of math problems is difficult, and it is a bit difficult for me to do it. Don't lose heart! Come on!

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